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Someone

Need Help #SoalUNIMED2012

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Anyone,, bisa tlg dibantu?

Tentukan penyelesaian dari persamaan berikut.

$(1+{\frac{1}{x}})^{x+1}=(1+{\frac{1}{2012}})^{2012}$

Dan yg 1 lagi...

Carilah semua penyelesaian $(x,y)$ dari persamaan

${x^2}(y-1)+{y^2}(x-1)=1$

Thanks perhatian & bantuannya

Edited by Someone

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3 hours ago, Syukri Lukman said:

X+1=-2012  ----> (x+1)/x = 2012/2013

X= -2013

Sip pak...mkasih...

Btw gmn yahh ngebuktiin kalo ga ada solusi lain slain itu pak?

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14 hours ago, Syukri Lukman said:

X+1=-2012  ----> (x+1)/x = 2012/2013

X= -2013

Kalau $x+1=-2012$ ntar $x=-2011$ lho..

Jadinya $(x+1)/x=2012/2011$

:smile:

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