salmanhiro

UTS 1 Matematika IIA ITB 2017 (Bagian A nomor 1)

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On 3/23/2017 at 11:44 PM, salmanhiro said:

Nomor 1 Bagian A

 

Hitunglah 2x22x3dx∫2x2−2x−3dx

Karena $x^2 - 2x - 3 = (x-3)(x+1)$ maka

 

$2 \times LHS = \int (x-3)^{-1} dx - \int (x+1)^{-1} dx = ln(x-3) - ln(x+1) + C = ln (x-3)/(x-1) + C $

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