Jump to content
Nur Mutmainnah Rahim

mencari bentuk sederhana (teori bilangan)

Recommended Posts

Hmm mungkin bisa difaktor kan stiap sukunya? Kayak $n^3 - 1 = (n - 1)(n^2 + n + 1)$ sama $n^3 + 1 = (n + 1)(n^2 - n + 1)$? :)

  • Upvote 1

Share this post


Link to post
Share on other sites
On 5/1/2017 at 5:54 PM, donjar said:

Hmm mungkin bisa difaktor kan stiap sukunya? Kayak n31=(n1)(n2+n+1)n3−1=(n−1)(n2+n+1) sama n3+1=(n+1)(n2n+1)n3+1=(n+1)(n2−n+1) ? :)

Iya.. terus perhatikan bahwa \(n^2+n+1=(n+1)^2-(n+1)+1\)

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now


×