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No 7

Spoiler

Agar genap, maka bilangan kuadrat sempurna tidak termasuk dalam kelompok tersebut. Nilai $0 <n^2<1000$ sehingga nilai $n \in \{1,2,3,...,31\}$. Sehingga banyak nilai $n$ yang memenuhi $1000 - 31 = 969$.

 

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