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Dua lingkaran standar

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Diberikan sebuah segitiga $ABC$ dengan $D$ di sisi $BC$. Sebuah garis yang melewati $D$ memotong sisi $AB$ di $X$ dan sinar $AC$ di $Y$. Lingkaran luar segitiga $BXD$ memotong lingkaran luar $\omega$ dari segitiga $ABC$ lagi di titik $Z \neq B$. Garis-garis $ZD$ dan $ZY$ masing-masing memotong $\omega$ lagi di $V$ dan $W$. Buktikan bahwa $AB = VW$.


APMO 2015 no. 1 oleh Warut Suksompong, Thailand

Edited by donjar

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