Jump to content
Sign in to follow this  
ivanwangsa

$\sum \frac{a}{1+3bc+k(b-c)^2} \geq \frac34$

Recommended Posts

Misalkan $a,b,c$ adalah bilangan riil tak negatif sehingga $a+b+c=1$. Tentukan nilai terbesar $k$ sehingga ketaksamaan berikut berlaku \[\frac{a}{1+3bc+k(b-c)^2} + \frac{b}{1+3ca+k(c-a)^2} + \frac{c}{1+3ab+k(a-b)^2} \geq \frac34.\]


Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

Sign in to follow this  

×