Agita Phasa

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  1. Langsung kepikiran 10a + b maksimal bernilai 99, jadi TM hhe
  2. a + b + c = 19 ... (1) (a-1)/(b-1) = 1/3 -> 3a - b = 2 ... (2) (b+3)/(c+3) = 5/6 -> 6b - 5c = -3 ... (3) pers. 2 dan 3: -6b + 18a = 12 6b - 5c = -3 ---------------------- + 18a - 5c = 9 ... (4) pers. 2 dan 1: 3a - b = 2 a + b = 19 - c ---------------------- + 4a + c = 21 ... (5) pers. 4 dan 5: 18a - 5c = 9 20a + 5c = 105 ------------------------ + 38a = 114 a = 3 b = 7 c = 9 Selisih bilangan terbesar dengan terkecil = 9 - 3 = 6
  3. Tidaak ._. abab = k^2 1000a + 100b + 10a + b = k^2 1010a + 101b = k^2 101(10a + b) = k^2 101 = bilangan prima 10a + b = 101 TM
  4. 5. f(x/3) = x^2 + 2x + 3 x/3 = 3z x = 9z f(3z) = (9z)^2 + 2 (9z) + 3 = 81z^2 + 18z + 3 81z^2 + 18z + 3 = 12 81 z^2 + 18z - 9 = 0 Jumlah semua nilai z = -18/81 = - 2/9 CMIIW ._\
  5. no. 4 nguli ._. yang bilangan genap dibuang, trus 5 juga, sisa 1, 3, 7, 9, dikombinasiin jadi bilangan 2 digit sekalian dicoba2 prima apa bukan hho. p = 11, 13, 17, 37, 79 -> ada 5. cmiiw ._.